INSTITUTO TECNOLOGICO DE TIJUANA
1.- EL ÁREA DE UN TRIANGULO CUYOS VÉRTICES SON:
P1 (2, 2,0)
P2 (-1, 0,2)
P3 (0, 4,3)
P1P2= -3,-2,2
P1P3= -2, 2,3
Producto cruzado:
P1P2 X P1P3 =
i , j , k
-3 , -2, 2
-2 , 2 , 3
= ((-2) (3)- (2) (2)) i - ((-3) (3)- (-2) (2)) j –((-2) (-2) - (-3) (2))
= ((-6) - (4)) i – ((-9) - (-4)) j - ((4)- (-6)) k
= -10 i +5 j -10k
// P1P2 X P1P3 //
=√ (-10)2 + (5)2 + (-10)2
= √100 +25 + 100
=√225
=15
Norma:
A= ⅟2 // P1P2 X P1P3 //
A= ⅟2(15)
A= 7.5 u
********************************************************************
Sea:
µ = (2, -1, 3)
v = (0, 1, 7)
w = (1, 4, 5)
a) (µ x v) x (v x w)
a) (µ x v) x (v x w)
(µ x v)=
i , j , k
2 , -1, 3
0 , 1 , 7
= ((-1) (7) - (1) (3)) i - ((2) (7) - (0) (3)) j + ((2) (1) - (0) (-1)) k
= ((-7) - (3)) i - ((14) - (0)) j + ((2) - (0)) k
= -10i, -14j ,+2k
(v x w) =
i , j , k
0 , 1 , 7
1 , 4 , 5
= ((1)(5) - (4)(7)) i - ((0)(5) - (1)(7)) j + ((0)(4) - (1) (1)) k
= ((5)- (28)) i - ((0) - (7)) j + ((0) - (1))k
= -23i ,+7j ,-1k
(µ x v) x (v x w)=
i , j , k
-10 , -14 , +2
-23 , 7 , -1
= ((-14) (-1) - (7)(2)) i - ((-10)(-1) - (-23)(2)) j + ((-10)(7) - (-23)(-14)) k
= ((+14) - (14)) i - ((+10) - (+46)) j + ((-70) - (322)) k
= 0 I, -56 j ,-392 k
b) µ x (v-2w)
w= (1,4,5)
2w=(2,8,10)
(v-2w) = -2,-7,-3
(v-2w) = -2,-7,-3
i , j , k
2 , -1 , 3
-2 ,-7 , -3
=((-1)(-3) - (-7)(3)) i - ((2)(-3) - (-2)(3)) j + ((2)(-7) - (-2)(-1)) k
=((-1)(-3) - (-7)(3)) i - ((2)(-3) - (-2)(3)) j + ((2)(-7) - (-2)(-1)) k
=((3) - (-21)) i - ((-6) - (-6)) j +((-14) - (2)) k
= +24i , 0j, -16k
c) (µ x v) -2w
c) (µ x v) -2w
(µ*v)=
i , j , k
2 , -1 , 3
0 , 1 , 7
=((-1) (7) - (1) (3)) i - ((2)(7) - (0)(3))j + ((2)(1) - (0)(-1)) k
=((-7) - (3)) i - ((14) - (0)) j - ((2) - (0)) k
= -10i, -14j, +2k
w = 1,4,5
2w = 2,8,10
(µ x v) -2w=
-10 , -14,+2
-2, -8, -10
= -12, -22, -8
****************************************************************
Hallar el área del triangulo que tiene vértices P,Q,R
P (2, 0, -3)
Q (1, 4, 5)
R (7, 2,9)
R (7, 2,9)
PQ = -1, 4, 8
PR = 5, 2, 12
PQ*PR =
i , j , k
-1, 4 , 8
5 , 2, 12
= ((4) (12)- (2)(8))i - ((-1)(12) - (5)(8))j -((-1) (2) - (5)(4)) k
=((48) - (16)) i- ((-12) - (40))j - ((-2) (-20))k
=32i +52j +22k
// PQ*PR//
// PQ*PR//
= √(32)2 + (52)2 + (22)2
= √1024 + 2704 + 484
= √4212 = 64.89
A = 1/2 // PQ*PR//
= √1024 + 2704 + 484
= √4212 = 64.89
A = 1/2 // PQ*PR//
A=1/2 (64.89)
A=32.44 u